8x^2+53x-21=

Solution for 8x^2+53x-21= equation:

8x^2+53x-21=

We move all terms to the left:

8x^2+53x-21-()=0

We add all the numbers together, and all the variables

8x^2+53x=0

a = 8; b = 53; c = 0;
Δ = b2-4ac
Δ = 532-4·8·0
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-53}{2*8}=\frac{-106}{16}
=-6+5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+53}{2*8}=\frac{0}{16}
=0
$